Answer:
Object will be at a distance of 358098.6 km from the source
Step-by-step explanation:
We have given angle = 0.0008 degree [tex]=\frac{0.0008\times \pi }{180}=4.444\times 10^{-6}\pi[/tex]
Radius is given = 2.50 km
Linear size of the object will be equal to diameter
So linear size = 2.5×2 = 5 km
We know that linear size [tex]=distance \times \Theta[/tex]
So [tex]5=d\times 4.444\times 10^{-6}\pi[/tex]
d = 358098.6 km
