Answer:
a) 0.72
b) 0.98
Step-by-step explanation:
We are given the following information in the question:
P(passing maths exam) = P(m) = 0.9
P(passing Spanish exam) = P(s) = 0.8
It is assumed that the results of the two exams are independent of each other.
a) probability that she passes both exams
By assumption of independence, we can write:
[tex]P(\text{passes both exam} = P(M\cap S) \\=P(M)\times P(S) = 0.8\times 0.9 = 0.72[/tex]
0.72 is the probability that Josie will pass both the exams.
b) probability that Josie passes at least one of the exam
[tex]P(\text{at least one of the exams}) = P(M\cup S)\\= P(M) + P(S) - P(M\cap S)\\= 0.9 + 0.8 - 0.72 = 0.98[/tex]
0.88 is the probability that Josie passes at least one of the exams.
