Respuesta :
Answer:
The population of bacteria after 6 days is 2,313.06
Step-by-step explanation:
Given as :
The initial population of bacteria = i = 1,000 bacteria
The growth rate of bacteria per day = 15%
Let The population of bacteria after 6 days = f
The time period of growth = 6 days
Now, According to question
The population of bacteria after 6 days = initial population × [tex](1+\dfrac{\textrm rate}{100})^{\textrm time}[/tex]
Or, f = i × [tex](1+\dfrac{\textrm r}{100})^{\textrm t}[/tex]
Or, f = 1000 × [tex](1+\dfrac{\textrm 15}{100})^{\textrm 6}[/tex]
Or, f = 1000 × [tex](1.15)^{6}[/tex]
Or, f = 1000 × 2.31306
∴ f = 2,313.06
So,The population of bacteria after 6 days = f = 2,313.06
Hence,The population of bacteria after 6 days is 2,313.06 Answer
Answer:
A, y = 1,000(1.15)6; 2,313 bacteria
Step-by-step explanation:
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