How many years will it take for an initial investment
of$40,000 to grow to $60,000? Assume a rate of interest of
10%compounded continuously.

Respuesta :

Answer: It will take 4.05 years for an initial investment  of $40,000 to grow to $60,000.

Step-by-step explanation:

The exponential growth equation (Compounded continuously) is given by :-

[tex]A= Pe^{rt}[/tex]               (1)

, where r = rate of growth (in decimal)

t= time

P= initial amount.

As per given , we have

P= $40,000

A = $60,000

r = 10% =0.10

Put values in (1) , we get

[tex]60000= (40000)e^{(0.10)t}[/tex]

[tex]1.5=e^{(0.10)t}[/tex]   [Divide both sides by 40000]

[tex]1.5=e^{0.1t}[/tex]  

Taking natural log on both sides , we get

[tex]\ln(1.5)=0.1t[/tex]

[tex]0.405465=0.1t[/tex]

[tex]\Rightarrow\ t=\dfrac{0.405465}{0.1}=4.05465\approx4.05\text{ years}[/tex]

Hence, it will take 4.05 years for an initial investment  of $40,000 to grow to $60,000.