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Consider triangles with the following measurements. If two sides are given, use the law of cosines to find the
measure of the third side. If three sides are given, use the law of cosines to find the measure of the angle between
a and ????.
a. a = 4, ???? = 6, m∠???? = 35°
b. a = 2, ???? = 3, m∠???? = 110°
c. a = 5, ???? = 5, m∠???? = 36°
d. a = 7.5, ???? = 10, m∠???? = 90°
e. a = 4.4, ???? = 6.2, m∠???? = 9°
f. a = 12, ???? = 5, m∠???? = 45°
g. a = 3, ???? = 6, m∠???? = 60°
h. a = 4, ???? = 5, c = 6
i. a = 1, ???? = 1, c = 1
j. a = 7, ???? = 8, c = 3
k. a = 6, ???? = 5.5, c = 6.5
l. a = 8, ???? = 5, c = 1
m. a = 4.6, ???? = 9, c = 11.9

Respuesta :

erturkmemmedli

Answer:

Answers are in explanation part.

Step-by-step explanation:

Law of Cosines for side c: [tex]c=\sqrt{a^2+b^2-2ab\cos C}[/tex]

a) c = 3.561

b) c = 4.136

c) c = 3.09

d) c = 12.5

e) c = 1.978

f) c = 9.173

g) c = 5.196

Law of Cosines for angle C: [tex]C=cos^{-1}(\frac{a^2+b^2-c^2}{2ab})[/tex]

h) C = 82.819°

i) C = 60°

j) C = 21.787°

k) C = 68.676°

l) Sides (8, 5, 1) cannot form a triangle. It is impossible.

m) C = 118.454°

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