Respuesta :
Answer: a) The rate constant, k, for this reaction is [tex]0.00516s^{-1}[/tex]
b) No [tex]t_{\frac{1}{2}}[/tex] does not depend on concentration.
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
[tex]A\rightarrow products[/tex]
Given: Order with respect to [tex]A[/tex] = 1
Thus rate law is:
a) [tex]Rate=k[A]^1[/tex]
k= rate constant
[tex]0.00250=k[0.484]^1[/tex]
[tex]k=0.00516s^{-1}[/tex]
The rate constant, k, for this reaction is [tex]0.00516s^{-1}[/tex]
b) Expression for rate law for first order kinetics is given by:
[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
[tex]t_{\frac{1}{2}}=\frac{2.303}{k}\log\frac{100}{50}[/tex]
[tex]t_{\frac{1}{2}}=\frac{0.69}{k}[/tex]
Thus [tex]t_{\frac{1}{2}}[/tex] does not depend on concentration.
