Answer:
Final speed will be 7.60 m /sec
Explanation:
We have given horizontal force F = 199 N
Mass of the cart = 55 kg '
From newton's law acceleration will be [tex]a=\frac{F}{M}=\frac{199}{55}=3.618m/sec^2[/tex]
As initially cart is at rest so initial velocity u = 0 m/sec
Distance traveled s= 8 m
From third equation of motion
[tex]v^2=u^2+2as[/tex]
[tex]v^2=0^2+2\times 3.618\times 8[/tex]
v = 7.60 m /sec
