contestada

A ship traveling east at 25 mph is 10 miles from the harborwhen a
second ship leaves the harbor traveling east at 35 mph. Howlong
will it take the second ship to catch up with the firstship?

Respuesta :

Answer:

Time taken by second ship to catch up first is 1 hour

Step-by-step explanation:

Let the distance of the destination from the harbor is x

It is given that first ship is 10 miles from the harbor 'So distance traveled by first ship = x - 10

Speed = 25 mph

So time taken taken [tex]=\frac{x-10}{25}[/tex]

And time taken by second ship to reach the destination [tex]=\frac{x}{35}[/tex]

Now [tex]\frac{x-10}{25}=\frac{x}{35}[/tex]

[tex]35x-350=25x[/tex]

[tex]x=35mile[/tex]

So time taken by second ship will be equal to [tex]\frac{35}{35}=1hour[/tex]

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