Answer: The required probability is 0.83.
Step-by-step explanation: Given that a person tosses a normal 6- sided die.
We are to find the probability that he will not roll a 2.
Let S denote the sample space for the experiment and E denote the event of not rolling a 2.
Then, S = {1, 2, 3, 4, 5, 6} and E = {1, 3, 4, 5, 6}.
That is, n(S) = 6 and n(E) = 5.
Therefore, the probability of event E is given by
[tex]P(E)=\dfrac{n(E)}{n(S)}=\dfrac{5}{6}=0.83.[/tex]
Thus, the required probability is 0.83.
