Mason starts walking from home at 3.7 mph. Ema leaes to follow
48 minutes later, walking at 4.1 mph. How long will it take Ema to
catch up tp Mason ?

Respuesta :

Answer:

It will take Emma 7.4 hours to catch Mason.

Step-by-step explanation:

Let's build the equations of motion for both Mason and Emma, starting at the minute 48.

These equations have the following format:

[tex]S(t) = S(0) + vt[/tex]

In which S is the position after t minutes, S(0) is the initial position and v is the velocity, in miles per hour.

Mason

Mason walks at 3.7 mph. So [tex]v = 3.7[/tex].

48 minutes is 0.8 hour. So at 48 minutes, his position is 0.8*3.7 = 2.96. So S(0) = 2.96.

Mason's equation of motion is:

[tex]S_{M}(t) = 2.96 + 3.7t[/tex]

Emma

Emma starts at the position 0, with speed of 4.1mph. o

Emma's equation of motion is:

[tex]S_{E}(t) = 4.1t[/tex]

How long will it take Ema to catch up tp Mason ?

This will happen when they are at the same position. So

[tex]S_{M}(t) = S_{E}(t)[/tex]

[tex]2.96 + 3.7t = 4.1t[/tex]

[tex]0.4t = 2.96[/tex]

[tex]t = 7.4[/tex]

It will take Emma 7.4 hours to catch Mason.