tokka1ahmed tokka1ahmed

08-01-2020
Physics

contestada

The speed of a 4.0-kg object is given by v = (2t) m/s, where t is in s. At what rate is the resultant force on this object doing work at t = 1 s?

Respuesta :

andrewinsoul andrewinsoul

19-01-2020

Answer:

4 J/s

Explanation:

m = 4.0kg

[tex]v_{1} = 2ms^{-1}[/tex]

t = 1s

F = ma = 4*(2-0)/1 = 4N

s = 0.5*a*1 = 0.5*2 = 1

Work done = 4 * 1 = 4J

At what rate at 1s = 4/1 = 4 Joule/second

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