Answer:
x = 16
Step-by-step explanation:
The equation is [tex]\log_{4} x = 2[/tex]
Now, converting this logarithmic equation into exponential equation, we get
[tex]x = 4^{2} = 16[/tex] (Answer)
Alternate solution:
Given, [tex]\log_{4} x = 2[/tex]
⇒ [tex]\log_{4}x = 2\log_{4}4[/tex]
{Since, we know that [tex]\log_{a}a = 1[/tex]}
⇒ [tex]\log_{4}x = \log_{4}4^{2} = \log_{4}16[/tex]
{Since, [tex]a\log b = \log b^{a}[/tex] is a property of logarithm}
Cancelling log from both sides we get,
⇒ x = 16 (Answer)
Answer:
[tex]x = 8^4[/tex]
Step-by-step explanation:
hey there,
< Here is what is given:
㏒[tex]_{8} x=4[/tex]
There's actually a lot of different ways you can remember this but the way I remember this is x is equal to 2nd to the power of last.
So 8 is the 2nd (since log is first), 4 is last (very last thing in the equation).
x = 8^4
You can use any of your own ways to remember this, but this is just my personal way. :) >
Hope this helped! Feel free to ask anything else.
