Respuesta :
Answer:
The chance is 1/16
Explanation:
Let the color allele be represented by B.
Let the length of hair be represented by L.
Pure breeding black = BB (dominant)
Pure breeding long-hair = ll (recessive)
Pure breeding siamese = bb
Pure breeding short-hair = LL
Pure breeding black, long-hair = BB ll
Pure breeding siamese, short-haired = bb LL
BB ll x bb LL
F1 offspring = 100% BbLl
Crossing two of the F1 offspring:
Bb Ll x Bb Ll
F2 offspring = 1 BBLL, 2 BBLl, 2 BbLL, 4 BbLl, 1 BBll, 2 Bbll, 1 bbLL, 2 bbLl, 1 bbll (see the aattched image)
Recall that: siamese color = bb and short-hair = LL
The proportion of bbLL genotype in the F2 offspring is 1/16.
The chance of producing a siamese colored, short-haired kitten is 1/16

Assume that these genes assort independently, there is no interact between them, and express complete dominance, the chance of producing a Siamese colored, short-haired kitten is 3/16.
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Available data:
Two diallelic genes. One codes for color and the other one for hair length.
Color Gene
- B dominant allele that codes for black
- b recessive allele that codes for siamese
Hair length
- S dominant allele that codes for short
- s recessive allele that codes for long
We will assume that these genes assort independently, they do not interact with each other, and express complete dominance.
1st Cross: a black long-haired cat with a Siamese, short-haired cat
Parentals) BBss x bbSS
F1) 100% BbSs
2nd Cross: F1 male with female
Parentals) BbSs x BbSs
Gametes) BS, Bs, bS, bs BS, Bs, bS, bs
Punnett square) BS Bs bS bs
BS BBSS BBSs BbSS BbSs
Bs BBSs BBss BbSs Bbss
bS BbSS BbSs bbSS bbSs
bs BbSs Bbss bbSs bbss
F1) Phenotypes
- 9/16 Black and short-haired cats, B-S-
- 3/16 Black and long-haired cat, B-ss
- 3/16 Siamese and short-haired cat, bbS-
- 1/16 Siamese and long-haired cat, bbss
Note: the symbol - represents either a dominant or recessive allele
The probability of getting a siamese cat with short hair, bbS-, is 3/16.
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Related link: https://brainly.com/question/10747731