Respuesta :
[tex]\frac{11}{7}[/tex] times the length of nathan’s bike ride was moo’s bike ride
Solution:
Given that, Moo bikes [tex]5\frac{1}{2}[/tex] miles and Nathan mike [tex]3\frac{1}{2}[/tex] miles
To find: number of times the length of nathan’s bike ride was moo’s bike ride
From given question,
Length of Moo bike ride = [tex]5\frac{1}{2}[/tex] miles
[tex]\rightarrow 5\frac{1}{2} = \frac{ 2 \times 5 + 1}{2} = \frac{11}{2} \text{ miles }[/tex]
Length of nathan bike ride = [tex]3\frac{1}{2}[/tex] miles
[tex]\rightarrow 3\frac{1}{2} = \frac{2 \times 3 + 1}{2} = \frac{7}{2} \text{ miles}[/tex]
Number of times the length of nathan’s bike ride was moo’s bike ride is given by:
Let "n" be the number of times
Therefore,
Length of Moo's bike ride = n x Length of nathan bike ride
[tex]\frac{11}{2} = n \times \frac{7}{2}\\\\11 = 7n\\\\n = \frac{11}{7}[/tex]
Thus [tex]\frac{11}{7}[/tex] times the length of nathan’s bike ride was moo’s bike ride
