Respuesta :
Answer:
The quantity of 70% saline solution chemist need is 4 liters
Step-by-step explanation:
Given as :
The quantity of 25% saline solution = 8 liters
Let The quantity of 70% saline solution chemist need = x liters
The quantity of 40% saline solution mixture = (x+8) liters
Now, According to question
∵The mixture is created with solutions
So, 25% of quantity of saline + 70% of quantity of saline = 40% of quantity of mixture
Or, 25% of 8 liters + 70% of x liters = 40% of (x+8) liters
Or, [tex]\dfrac{25}{100}[/tex] × 8 + [tex]\dfrac{70}{100}[/tex] × x = [tex]\dfrac{40}{100}[/tex] × (x+8)
Or, [tex]\frac{25\times 8}{100}[/tex] + [tex]\frac{70\times x}{100}[/tex] = [tex]\frac{40\times (x +8)}{100}[/tex]
Or, 200 + 70 x = 40 × (x+8)
Or, 200 + 70 x = 40 x + 320
Or, 70 x - 40 x = 320 - 200
Or, 30 x = 120
∴ x = [tex]\dfrac{120}{30}[/tex]
i.e x = 4 liters
So,The quantity of 70% saline solution chemist need = x = 4 liters
Hence, The quantity of 70% saline solution chemist need is 4 liters Answer
The chemist needs 4 liters of the 70% solution
25% of saline solution = 25% of 8 liters
25% of saline solution = 0.25 x 8 = 2 liters
Let 70% of the saline solution be x liters
The salt = 8 + x
25% of saline solution + 70% of the saline solution = 40% of salt
2 + (70/100)x = (40/100)(8 + x)
2 + 0.7x = 0.4(8 + x)
2 + 0.7x = 3.2 + 0.4x
Collect like terms
0.7x - 0.4x = 3.2 - 2
0.3x = 1.2
x = 1.2 / 0.3
x = 4
The chemist needs 4 liters of the 70% solution
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