If you wanted to combine equal numbers of Na and Cl atoms in a flask, how much Cl would you have to add if you added 23g of NA?

Respuesta :

Answer: The mass of chlorine atom required to combine is 35.5 grams.

Explanation:

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]      .....(1)

  • For sodium:

Given mass of sodium = 23 g

Molar mass of sodium = 23 g/mol

Putting values in equation 1, we get:

[tex]\text{Moles of sodium}=\frac{23g}{23g/mol}=1mol[/tex]

According to mole concept:

1 mole of an atom contains [tex]6.022\times 10^{23}[/tex] number of particles

So, 1 mole of sodium will contain = [tex](1\times 6.022\times 10^{23})=6.022\times 10^{23}[/tex] number of atoms

Number of atoms of chlorine = Number of atoms of sodium = [tex]6.022\times 10^{23}[/tex] = 1 mole

Now, calculating the mass of chlorine required by using equation 1:

Moles of chlorine = 1 mole

Molar mass of chlorine = 35.5 g/mol

Putting values in equation 1, we get:

[tex]1mol=\frac{\text{Mass of chlorine}}{35.5g/mol}\\\\\text{Mass of chlorine}=(1mol\times 35.5g/mol)=35.5g[/tex]

Hence, the mass of chlorine atom required to combine is 35.5 grams.