Answer:
[tex] -1.42 m/s^2[/tex] is the car's acceleration.
Explanation:
Initial velocity of the driver = u = 14 m/s
Final velocity of the driver = v = 5.5 m/s
Duration of time in which 14 m/s velocity is changed to 5.5 m/s = t = 6.0 s
Acceleration of the driver = a
Using first equation of motion: v = u + at
[tex]5.5 m/s=14 m/s+a\times (6.0 s)[/tex]
[tex]5.5 m/s-14m/s =a\times 6.0 s[/tex]
[tex]-8.5 m/s=a\times 6.0 s[/tex]
[tex]a=\frac{-8.5 m/s}{6.0 s}=-1.417 m/s^2\approx -1.42 m/s^2[/tex]
Negative sign indicates the that is deceleration is occurring that is speed of the car is decreasing.
