Respuesta :
Answer:
It will take 27 seconds for a cyclist to stop completely.
Explanation:
Initial velocity of the cyclist= u = 13.5 m/s
Acceleration of the driver = a = [tex]-0.50 m/s^2[/tex]
Final velocity of the cyclist = v = 0
Duration of time in which 13.5 m/s velocity is changed to 0 = t = ?
Using first equation of motion:
v = u + at
[tex]0 =13.5 m/s+(-0.50 m/s^2)\times (t)[/tex]
[tex]-13.5 m/s=-0.50 m/s^2\times t[/tex]
[tex]t=\frac{-13.5 m/s}{-0.50 m/s^2}=27 s[/tex]
It will take 27 seconds for a cyclist to stop completely.
Acceleration is the rate at which velocity changes with time, in terms of both speed and direction. A point or an object moving in a straight line is accelerated if it speeds up or slows down.
Acceleration-
Because acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is also a vector quantity.
It will take 27 seconds for a cyclist to stop completely.
Initial velocity of the cyclist= u = 13.5 m/s
Acceleration of the driver = a = [tex]-0.50m/s^2[/tex]
Final velocity of the cyclist = v = 0
Duration of time in which 13.5 m/s velocity is changed to 0 = t =?
Using first equation of motion:
v = u + at
[tex]o=13.5m/s +[/tex][tex](-0.50m/s^2)[/tex] × [tex](t)[/tex]
[tex]-13.5m/s[/tex] [tex]=-0.50m/s^2[/tex] × [tex]t[/tex]
[tex]t= -13.5m/s} \atop -0.50m/s^2 \right.[/tex][tex]= 27 s[/tex]
It will take 27 seconds for a cyclist to stop completely.
Thus, it will take 27 seconds for the cyclist.
Learn more about acceleration here:
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