Answer: [tex]x^{-4}=\frac{1}{x^{4}}[/tex]
Step-by-step explanation:
We have the following expression:
[tex](\sqrt[3]{x^{2}} \sqrt[6]{x^{4}})^{-3}[/tex]
Which can also be written as:
[tex](x^{\frac{2}{3}} x^{\frac{4}{6}})^{-3}[/tex]
Since we have exponents with the same base [tex]x[/tex] inside the parenthesis, we can sum both exponents:
[tex](x^{\frac{4}{3}})^{-3}[/tex]
Now, we have to multiply the exponent out of the parenthesis with the inner exponent and have the following result:
[tex]x^{-4}=\frac{1}{x^{4}}[/tex]
