Respuesta :
Answer:
a) 0.172
b) 0.167
c) 0.1404
Step-by-step explanation:
Margin of error, E = [tex]2\times\sqrt{\frac{p(1-p)}{n}}[/tex]
here,
p = probability of the event
n = sample size
a) n = 30
p = 10 ÷ 30 = 0.333
Therefore,
E = [tex]2\times\sqrt{\frac{0.333(1-0.333)}{30}}[/tex]
= 2 × 0.0861
= 0.172
b) n = 30
p = 21 ÷ 30 = 0.7
Therefore,
E = [tex]2\times\sqrt{\frac{0.7(1-0.7)}{30}}[/tex]
= 2 × 0.0836
= 0.167
c) n = 30
p = 22 ÷ 50 = 0.44
Therefore,
E = [tex]2\times\sqrt{\frac{0.44(1-0.44)}{50}}[/tex]
= 2 × 0.0702
= 0.1404
