Explanation:
Let us assume that Z is the energy transported across an area of [tex]1.00 cm^{2}[/tex] per hour by an electromagnetic wave with an r.m.s speed of 21.5 V/m.
Therefore, first we will calculate the current as follows.
I = [tex]\frac{E_{rms^{2}}}{c \times \mu_{o}}[/tex]
= [tex]\frac{10^{-4} \times 3600 \times (21.5)^{2}}{3 \times 10^{8} \times 4 \times 3.14 \times 10^{-7}}[/tex]
= 0.441 J
Therefore, we can conclude that 0.441 J energy is transported across a given EM wave.
"0.441 J" energy is transported.
Whenever charge seems to be maintained in whatsoever form, some electric property has been linked among each point throughout the space.
This same electric field might well be conceived of as one of the force per unit positive (+) ions which would be exerted well before appearance of the charged particle disturbs the area.
According to the question,
Area, [tex]A = 100 \ cm^2[/tex]
Speed, [tex]r.m.s = 21.5 \ V/m[/tex]
As we know,
→ [tex]I = \frac{E_{rms}^2}{c\times \mu_0}[/tex]
By substituting the values, we get
[tex]= \frac{10^{-4}\times 3600\times (21.5)^2}{3\times 10^8\times 4\times 3.14\times 10^{-7}}[/tex]
[tex]= 0.441 \ J[/tex]
Thus the above answer is correct.
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