Answer:
A resistance of 445.625 ohm must be added in parallel
Explanation:
Here unit of resistance is given watt which will be ohm
We have given equivalent resistance R = 115 ohm
Resistance of one resistor [tex]R_1=155ohm[/tex]
We have to find the value of [tex]R_2[/tex]
For parallel combination equivalent resistance is given by
[tex]\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}[/tex]
So [tex]\frac{1}{115}=\frac{1}{155}+\frac{1}{R_2}[/tex]
[tex]\frac{1}{R_2}=0.00224[/tex]
[tex]R_2=445.625ohm[/tex]
So a resistance of 445.625 ohm must be added in parallel
