To solve this problem we will use a free body diagram that allows us to determine the Normal Force.
In general, the normal force would be equivalent to
[tex]N = mgcos\theta[/tex]
Since the skier is standing on two skis, his weight will be divide by two
[tex]N' = \frac{mgcos\theta}{2}[/tex]
Pressure is given as the force applied in a given area, that is
[tex]P = \frac{F}{A}[/tex]
Replacing F with N'
[tex]P = \frac{N'}{A}[/tex]
[tex]P = \frac{\frac{mgcos\theta}{2}}{A}[/tex]
Our values are given as,
[tex]m = 58kg[/tex]
[tex]g = 9.8m/s^2[/tex]
[tex]\theta = 35\°[/tex]
[tex]A = 0.3m^2[/tex]
Replacing we have that
[tex]P = \frac{\frac{(58)(9.8)cos(35)}{2}}{0.3}[/tex]
[tex]P = 776.01Pa[/tex]
Therefore the pressure exerted by each ski on the snow is 776.01Pa
