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Show that at the bottom of a vertical mine shaft dug to
depthD, the measured value of ag will be
ag = ags(1 - D/R),
ags being the surface value. Assume thatEarth is a
uniform sphere of radius R.

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msakhile

Answer:

Please see attachment

Explanation:

Please see attachment

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Data;

  • D = bottom of a vertical mine shaft
  • ag =measured value of acceleration

The Gravitational Acceleration

Assuming that earth is a uniform sphere of radius R.

The net separation from the planet (r) = (R-D)

ag is the the gravitational acceleration at that point

[tex]m' = \rho * (4\pi/3) * (R-D)^3\\a_g = G*\rho *(4\pi /3)*(R-D)\\a_g = \frac{4*\pi * G * R * \rho }{3} \\a_g = a_g_s (1 - D/R)[/tex]

Learn more on gravitational acceleration here;

https://brainly.com/question/17785701

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