Answer:
[tex]1.4007\times 10^{-8}\ N[/tex]
[tex]1.50075\times 10^{-6}\ N[/tex]
[tex]0.000000667\ N[/tex]
Explanation:
[tex]m_1[/tex] = Mass of baby = 3 kg
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
r = Distance between objects
Gravitational force of attraction is given by
[tex]F=\dfrac{Gm_1m_2}{r^2}\\\Rightarrow F=\dfrac{6.67\times 10^{-11}\times 70\times 3}{1^2}\\\Rightarrow F=1.4007\times 10^{-8}\ N[/tex]
The force between baby and obstetrician is [tex]1.4007\times 10^{-8}\ N[/tex]
[tex]F=\dfrac{6.67\times 10^{-11}\times 3\times 2.7\times 10^{27}}{(6\times 10^{11})^2}\\\Rightarrow F=1.50075\times 10^{-6}\ N[/tex]
The force between the baby and Jupiter is [tex]1.50075\times 10^{-6}\ N[/tex]
[tex]F=\dfrac{6.67\times 10^{-11}\times 3\times 2.7\times 10^{27}}{(9\times 10^{11})^2}\\\Rightarrow F=0.000000667\ N[/tex]
The force between the baby and Jupiter is [tex]0.000000667\ N[/tex]
