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During light activity, a 70-kg person may generate 200 kcal
/h. Assuming that 20% of this goes into useful work and the
other80% is converted to heat, calculate the temperature rise of
thebody after 1.00 h if none of this heat were transferred to
theenvironment.

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Answer:

[tex]2.75387\ ^{\circ}[/tex]

Explanation:

m = Mass of person = 70 kg

c = Specific heat of human body = [tex]0.83\ J/kg^{\circ}C[/tex]

[tex]\Delta T[/tex] = Change in temperature

Time taken is 1 hour

Heat is given by

[tex]Q=mc\Delta T\\\Rightarrow \Delta T=\dfrac{Q}{mc}\\\Rightarrow \Delta T=\dfrac{0.8\times 200\times 1}{70\times 0.83}\\\Rightarrow \Delta T=2.75387\ ^{\circ}C[/tex]

The rise in temperature is [tex]2.75387\ ^{\circ}C[/tex]

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