Answer
given,
mass of satellite = 2400 Kg
speed of the satellite = 6.67 x 10³ m/s
acceleration of satellite = ?
gravitational force of the satellite will be equal to the centripetal force
[tex]F = \dfrac{mv^2}{r}[/tex]
[tex]F = \dfrac{2400\times (6.67\times 10^3)^2}{r}[/tex]
Assuming the radius of circular orbit = 8.92 x 10⁶ m
now,
[tex]F = \dfrac{2400\times (6.67\times 10^3)^2}{8.92\times 10^6}[/tex]
F = 11970.11 N
acceleration,
[tex]a = \dfrac{F}{m}[/tex]
[tex]a = \dfrac{11970.11}{2400}[/tex]
a = 4.98 m/s²
