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A 2.0 kg tumor is being irradiated by a radioactive source.The
tumor receives an absorbed dose of 12 Gy in a time of880 s. Each
disintegration of theradioactive source produces a particle that
enters the tumor anddelivers an energy of 0.40 MeV. Whatis the
activity N//t of
theradioactive source?

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Answer:

426136363636.36365 Bq

Explanation:

Grays = 12

Mass = 2 kg

Time = 880

Energy = 0.4 MeV

Activity is given by

[tex]Activity=\dfrac{Grays\times Mass}{Time\times 0.4}\\\Rightarrow Activity=\dfrac{12\times 2}{880\times 0.4\times 1.6\times 10^{-13}}\\\Rightarrow Activity=426136363636.36365\ Bq[/tex]

The activity N//t of the radioactive source is 426136363636.36365 Bq

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