In a diffraction experiment, light of 600nm wavelengthproduces
a first-order maximum 0.350 mm from the central maximum ona distant
screen. A second monochromatic source produces athird-order maximum
0.870 mm from the central maximum when itpasses through the same
diffraction grating. What is thewavelength of the light from the
second source?

Respuesta :

Answer:

λ≅[tex]4.97*10^{-4}nm[/tex]

λ≅497 nm

Explanation:

In order to find the wavelength of the light from the second source we are going follow the following procedure.

Formula:

Nλ=d*x/l

Where:

N is the order of maximum

λ is the wavelength

d is the distance from central maximum

x/l is the ratio

For first monochromatic source:

We will find the ratio x/l.

[tex]\frac{x}{l}[/tex]=Nλ/d

[tex]\frac{x}{l}=\frac{1*600*10^-^6}{0.350*10^-^3}[/tex]

[tex]\frac{x}{l}=1.71428[/tex]

For second monochromatic source:

Nλ=d*x/l

λ=[tex]\frac{d*x/l}{N}[/tex]

λ=[tex]\frac{0.870*10^-^3*1.71428}{3}[/tex]

λ≅[tex]4.97*10^{-4}nm[/tex]

λ≅497 nm