Respuesta :
Answer:
Explanation:
Given
thickness of soap bar t=2 cm
thickness underwater t'=1.5 cm
oil is poured in the water with specific gravity=0.6
Soap top surface is just level with the upper surface of oil i.e.
weight of soap is balance by buoyancy effect of oil and water
initially soap is balanced by water
[tex]\rho _s\times A\times 2\times g=\rho _w\times A\times 1.5\times g[/tex]
[tex]2\times \rho _s=1.5\rho _w[/tex]
if [tex]\rho _s=density\ of\ soap[/tex]
[tex]\rho _w=density of water[/tex]
[tex]A=area\of\ cross-section[/tex]
[tex]d=depth\ of\ soap\ in\ oil[/tex]
[tex]\rho _s\times A\times 2\times g=0.6\rho _w\times A\times d\times g+\rho _w\times A\times (2-d)\times g[/tex]
[tex]1.5\rho _w=0.6d\rho _w+\rho _w(2-d)[/tex]
[tex]1.5=0.6d+2-d[/tex]
[tex]0.4d=0.5[/tex]
[tex]d=\frac{5}{4}[/tex]
[tex]d=1.25\ cm[/tex]
