A solid disk has a mass of 162 kg and a radius of 1.30m. This
disk rotates about an axis through its center, like acompact discl
and has an angulaar speed of 18.0 rad/s. If allthe kinetic energy
of this disk were used to lift a 3.00 kg block,how high could the
block be lifted?

Respuesta :

Answer:

754.3 m

Explanation:

The moment of inertia of the solid disk:

[tex]I = mR^2/2[/tex]

Where m is the disk mass and R is the radius of the disk.

[tex]I = 162*1.3^2/2 = 136.89 kgm^2[/tex]

The angular kinetic energy of the disk is then:

[tex]E_k = I\omega^2/2 = 136.89 * 18^2/2 = 22176.18 J[/tex]

By law of energy conservation, this energy is converted to potential energy to pick up the 3kg block

let g = 9.8 m/s2

[tex]E_p = m_bgh = 22176.18 J[/tex]

where [tex]m_b[/tex] = 3 kg is the mass of block

[tex]3*9.8h = 22176.18[/tex]

[tex]h = \frac{22176.18}{3*9.8} = 754.3 m[/tex]