Respuesta :
Answer:
Period, T = 10.86 seconds
Frequency, f = 0.092 Hz
Wavelength, [tex]\lambda=39.257883151578\ m[/tex]
Speed, v = 3.61 m/s
Explanation:
It is given that,
A woman notices that a wave crest passes by, five more crests pass in a time of 54.0 .
The distance between two successive crests is, the wavelength of wave, [tex]\lambda=39.257883151578\ m[/tex]
(b)Frequency of a wave is given by number of oscillations per second such that,
[tex]f=\dfrac{n}{t}[/tex]
[tex]f=\dfrac{5}{54}[/tex]
f = 0.092 Hz
(a) Let T is the period of the wave. It is inverse of frequency of a wave such that,
[tex]T=\dfrac{1}{f}[/tex]
[tex]T=\dfrac{1}{0.092}[/tex]
T = 10.86 seconds
(c) The distance between two successive crest or trough is called wavelength of a wave, [tex]\lambda=39.257883151578\ m[/tex].
(d) The speed of a wave is given by :
[tex]v=f\lambda[/tex]
[tex]v=0.092\times 39.257883151578[/tex]
v = 3.61 m/s
Hence, this is the required solution.
