Answer:
The degree of polarization of the reflected light [tex]74.6^{\circ}[/tex]
Solution:
As per the question:
Refractive index, [tex]\mu = 1.5[/tex]
Angle of incidence, [tex]\angle i = 40^{\circ}[/tex]
Now,
To calculate the degree of polarization:
We know according to the laws of reflection, angle of incidence and angle of reflection are equal.
[tex]\angle i = \angle r = 40^{\circ}[/tex]
Also, from Brewster law:
[tex]\mu = \frac{sin p}{sin r}[/tex]
[tex]\musin r = sin p[/tex]
[tex]p = sin^{- 1}{1.5\times sin 40^{\circ}} = 74.6^{\circ}[/tex]
