Answer:
Velocity from second channel will be 1.6875 m/sec
Explanation:
We have given width of the channel , that is diameter of the channel 1 [tex]d_1[/tex] = 12 m
So radius [tex]r_1=\frac{d_1}{2}=\frac{12}{2}=6m[/tex]
Speed through the channel 1 [tex]v_1=0.75m/sec[/tex]
Width , that is diameter of the channel 2 [tex]d_2=4m[/tex]
So [tex]r_2=2m[/tex]
From continuity equation
[tex]A_1v_1=A_2v_2[/tex]
[tex]\pi \times 12^2\times 0.75=4\times \pi\times 4^2\times v_2[/tex]
[tex]v_2=1.6875m/sec[/tex]
So velocity from smaller channel will be 1.6875 m /sec