Answer:
Maximum charge will be [tex]6.66\times 10^{-9}C[/tex]
Explanation:
We have given force ion the moving charge [tex]F=10^{-12}N[/tex]
Maximum speed of the moving charge v = 30 m /sec
Magnetic field [tex]B=5\times 10^{-5}T[/tex]
We have to fond the charge
Force on moving charge is given by
[tex]F=qvB[/tex]
So [tex]10^{-12}=q\times 30\times 5\times 10^{-5}[/tex]
[tex]q=6.66\times 10^{-9}C[/tex]
Maximum charge will be [tex]6.66\times 10^{-9}C[/tex]