Answer:
P = 1235.7646 W
Explanation:
Given data:
height of raised sewage = 5.49 m
rate of sewage =1.89*10^6 lt/day
density of sewage = 1.050 kg/m^3
power is written as
[tex]P = \frac{work}{time}[/tex]
work = m g h
[tex] m - mass = ( \rho V)[/tex]
h -height
mass lifted per day [tex]= ( 1.89*10^6)(1.050)[/tex]
= 1984500 kg
time = 24 hours* 3600 seconds per hour
power[tex]P = \frac{( 1984500)(9.8)( 5.49)}{(24)(3600)}[/tex]
P = 1235.7646 W
