Answer:
[tex]41.7975\ ^{\circ}[/tex]
Explanation:
[tex]n_2[/tex] = Refraction index of water = 1.333
[tex]n_1[/tex] = Refraction index of air = 1
[tex]\theta_2[/tex] = Angle of sunlight = 30°
From Snell's law we have
[tex]\dfrac{n_1}{n_2}=\dfrac{sin\theta_2}{sin\theta_1}\\\Rightarrow \theta_1=sin^{-1}\dfrac{n_2sin\theta_2}{n_1}\\\Rightarrow \theta_1=sin^{-1}\dfrac{1.333sin30}{1}\\\Rightarrow \theta_1=41.7975\ ^{\circ}[/tex]
The angle measured from the vertical does the sunlight strike thesurface of the water is [tex]41.7975\ ^{\circ}[/tex]
