Answer:
a = 0.77 m/s^2
Explanation:
The centripetal acceleration is given as
[tex]a = \frac{v^2}{R}[/tex]
The velocity of the car can be calculated using the circumference of the track and the period of the car.
[tex]2\pi R = v T\\2\pi 2.6 = v 360\\v = 0.045 ~km/s = 45~m/s[/tex]
So, the acceleration is
[tex]a = \frac{45^2}{2.6\times 10^3} = 0.77~m/s^2[/tex]
