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A Roman centurion fires off a vat of burning pitch from
hiscatapult at 18.2m/s, 37 degrees above the horizontal.
a. how long was the vat in the air?
b. determine the horizontal component of the initial
velocityof the vat.
c. determine the range of the vat.

Respuesta :

princessesther2011

Answer:

(a) 1.11sec

(b) 14.37m/s

(c) 31.78m

Explanation:

U = 18m/s, A = 37°, g = 9.8m/s^2

(a) t = UsinA/g = 18sin37°/9.8 = 18×0.6018/9.8 = 1.11sec

(b) Ux = UcosA = 18cos37° = 18×0.7986 = 14.37m/s

(c) R = U^2sin2A/g = 18^2sin2(37°)/9.8 = 324sin74°/9.8 = 324×0.9613/9.8 = 31.78m

adedayo9

Answer:

a 5.995m

b 14.54m/s

C 31.84m

Explanation:

H= u^2 sin^2x/2g

H= 18.2^2 sin^2×37/2×10

H= 331.24× 0.362/20

H= 5.995m

Horizontal component of the Vat

Ux= ucos x ; x is the angle

Ux= 18.2 cos 37

Ux= 14.54m/s

Range = u^2 sin2x/g

18.2^2 sin 74/10

Range = 318.40/10

Range = 31.84m

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