Respuesta :
Answer:
The energy required to increase the temperature of the diatomic ideal gas by 1 degree C is 118.18 kJ.
Explanation:
Given that,
Volume = 100 m³
Temperature = 300 K
Suppose Consider heating it at constant pressure.
We need to calculate the energy required to increase the temperature of the diatomic ideal gas by 1 degree C
Using formula of heat energy
[tex]Q=nC_{p}\Delta T[/tex]
Where, n = numbers of moles of gas
[tex]C_{p}[/tex] =specific heat capacity
[tex]\Delta T[/tex] = change in temperature
We know that,
The specific heat capacity for diatomic ideal gas
[tex]C_{p}=\dfrac{7R}{2}[/tex]
Put the value into the formula of heat
[tex]Q=\dfrac{7}{2}nR\Delta T[/tex]
Substitute the value of nR into the formula
[tex]Q=\dfrac{7}{2}\dfrac{PV}{T}\tiiems\Delta T[/tex]
Here, P = pressure of the air
V = volume of the air
Put the value into the formula
[tex]Q=\dfrac{7}{2}\times\dfrac{1.013\times10^5\times100}{300}\times1[/tex]
[tex]Q=118183.3\ J[/tex]
[tex]Q=118.18\ kJ[/tex]
Hence, The energy required to increase the temperature of the diatomic ideal gas by 1 degree C is 118.18 kJ.
