Respuesta :
Answer:
Explanation:
Given
mass of bus along with travelers travelling in North direction is [tex]m_1=1.6\times 10^4 kg[/tex]
speed of bus towards North [tex]v_1=15.2 km/h\approx 4.22\ m/s[/tex]
mass of bus travelling in South direction is [tex]m_2=1.578\times 10^4 kg[/tex]
speed of bus [tex]v_2=12.2 km/h\approx 3.38\ m/s[/tex]
mass of each Passenger in south moving bus [tex]m_0=64.8 kg[/tex]
Momentum of North moving bus
[tex]P_1=m_1\times v_1[/tex]
[tex]P_1=1.6\times 10^4\times 4.22[/tex]
[tex]P_1=6.768\times 10^4 kg-m/s[/tex]
Momentum with south moving bus
[tex]P_2=m_2\times v_2+n\cdot m_0\times v_2[/tex]
[tex]P_2=(1.578\times 10^4+n\cdot 64.8 )\cdot 3.38[/tex]
For total momentum to be towards south
[tex]P_2-P_1[/tex] should be greater than 0
thus for least value of n
[tex]P_2=P_1[/tex]
[tex](1.578\times 10^4+n\cdot 64.8 )\cdot 3.38=6.768\times 10^4[/tex]
[tex]1.578\times 10^4+n\cdot 64.8=2.0023\times 10^4[/tex]
[tex]n=\frac{4243.6686}{64.8}=65.48\approx 66[/tex]
