Answer:
Step-by-step explanation:
a. The probability of selecting a 6 from the first draw and a 7 on the second draw when two balls are selected without replacement from a container with 10 balls numbered 1 to 10
Not independent because without replacement
Prob for both = [tex]\frac{1}{10} \frac{1}{9} \\=\frac{1}{90}[/tex]
b. The probability of selecting a 6 on the first draw and a 7 on the second draw when two balls are selected with replacement from a container with 10 balls numbered 1 to 10
Here independent because with replacement makes probability independent.
Prob for both = P(A) *P(B) = [tex]\frac{1}{10} *\frac{1}{10} \\=\frac{1}{100}[/tex]d
c. The probability that two people selected at random in a shopping mall on a very busy Saturday both have a birthday in the month of June. Assume that all 365 birthdays are equally
likely, and ignore the possibility of a February 29 leap-year birthday.
Here independent because one person birthday will not affect the other person birthday
Prob for both = [tex](\frac{30}{365})^2\\ =\frac{25}{5329}[/tex]
d. The probability that two socks selected at random from a drawer containing 10 black socks and 6 white socks will both be black
Prob for I sock black = 10/16 and II sock black if first sock is black = 9/15
Hence not independent
Prob for both = [tex]\frac{10C2}{16C2} \\=\frac{3}{8}[/tex]