Respuesta :
Answer:
Electric potential, [tex]V=3.52\times 10^{12}\ volts[/tex]
Explanation:
It is given that,
The magnitude of electric field, [tex]E=4.7\times 10^7\ V/m[/tex]
Distance between automobile engines that consists of metal conductors, [tex]d = 0.75\ mm = 7.5\times 10^4\ m[/tex]
Let V is the magnitude of the potential difference between the conductors. The relation between the electric field and the electric potential is given by:
[tex]V=E\times d[/tex]
[tex]V=4.7\times 10^7\ V/m \times 7.5\times 10^4\ m[/tex]
[tex]V=3.52\times 10^{12}\ volts[/tex]
So, the magnitude of the potential difference between the conductors is [tex]3.52\times 10^{12}\ volts[/tex]. Hence, this is the required solution.
