contestada

For the wing foil, dtermine the aerodynamic lift. Density
ofair=1.21 kg/m3. Area= 200m2.
Speed=150m/s,speed=100m/s.

Respuesta :

The lift is the force generated on a body that travels through a fluid, perpendicular to the speed of the incident current. The mathematical model is given as

[tex]F_L = \frac{1}{2} \rho A (V_t^2-V_u^2)[/tex]

Here,

[tex]\rho[/tex]= Density

A = Cross sectional Area

[tex]V_2[/tex] =  Upper Velocity

[tex]V_1[/tex] = Down Velocity

Our values are given as

[tex]\rho[/tex] =1.21 kg/m3.

A= 200m2.

[tex]V_2[/tex]=150m/s

[tex]V_1[/tex]=100m/s

Replacing we have,

[tex]F_L = \frac{1}{2} \rho A (V_t^2-V_u^2)[/tex]

[tex]F_L = \frac{1}{2} (1.21) (200) ((150)^2-(100)^2)[/tex]

[tex]F_L = 1512500N[/tex]

Therefore the areodynamic lift would be [tex]1.512*10^6N[/tex]