Answer:
T = 5.36 s
Explanation:
given,
depth of the mine shaft = 122.5 m
speed of the sound = 340 m/s
time taken = ?
time taken by the stone to reach at the bottom
using equation of motion
[tex]s = u t + \dfrac{1}{2}gt^2[/tex]
initial speed , u = 0 m/s
[tex]t = \sqrt{\dfrac{2s}{g}}[/tex]
[tex]t = \sqrt{\dfrac{2\times 122.5}{9.8}}[/tex]
t = 5 s
time taken by the sound to travel
d =v x t
[tex]t = \dfrac{d}{v}[/tex]
[tex]t = \dfrac{122.5}{340}[/tex]
t = 0.36 s
total time taken for the sound to reach carol after dropping the stone
T = 5 + 0.36
T = 5.36 s
