An archer's bow is drawn at its midpoint until the tension
inthe string is 1.20 times the force exerted by the archer. What
isthe angle between the two halves of the string?

Respuesta :

Answer:

θ= 131° and in radian  rad = 2.27  

Explanation:

We have find the angle as the tension in the string is 1.20 times the force.

as We have

F = 2.T.cos(θ/2)  

Angle can be found as

θ = 2×cos⁻¹(1/(1.2×2))......................2 times because angle between the two halves of the string

θ= 131° and in radian  rad = 2.27