On a ski weekend in Colorado, Bob whose mass is 75.0kg, skies downa
hill that is inclined at an angle of 15.0 degrees to thehorizontal
and has a vertical rise of 25.0m. How much work is doneby gravity
on Bob as he goes down the hill?

Respuesta :

Answer: W = 18375J

Explanation:

Given;

Mass of bob m= 75kg

Vertical rise of plane d = 25.0m

Angle of elevation = 15°

Acceleration due to gravity = 9.8m/s2

Workdone is given by force time distance.

The workdone by gravity will be given by;

W = F×d

Where F is the weight of bob and d is the vertical distance covered by bob.

F = m*a = m×g

d = 25m

So,

W = m×g×d

W = 75 ×9.8×25

W = 18375J

Note: you may not need the angle of elevation to calculate the workdone by gravitational force.

Or we can also calculate it using

W = mgsinx × d

Where in this case d is the total length travelled on the inclined plane.

(We will still arrive at the same answer)

The Work done will be "18375 J".

Given values are:

Mass of bob,

  • m = 75 kg

Vertical rise,

  • d = 25.0 m

Angle of deviation,

  • [tex]\Theta[/tex] = 15°

As we know,

→ [tex]W = F\times d[/tex]

or,

→ [tex]W = m\times g\times d[/tex]

By substituting the values, we get

→      [tex]= 75\times 9.8\times 25[/tex]

→      [tex]= 18375 \ J[/tex]

Thus the above approach is right.    

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