Respuesta :
Answer:
Products: Each product can be mentally solved, we need to multiply each factor by the units digit and then add it to the product with the tenths, as follows
1. [tex]8 \times 34 \implies (8\times 4)+ (8 \times 30)=32+240=272[/tex]
2. [tex]5 \times 47 = (5 \times 7)+ (5 \times 40)=35+200=235[/tex]
3. [tex]12 \times 43= (12 \times 3)+(12 \times 40)=36+480=516[/tex]
4. [tex]8 \times 33=(8 \times 3) + (8 \times 30)=24+240=264[/tex]
5. [tex]6 \times 4.4=60 \times 44=(60 \times 4)+(60 \times 40)=240+2400=2640 \implies 26.40[/tex]
6. [tex]7 \times 2.9= 70 \times 29=(70 \times +9)+(70 \times 20)=630+1400=2030 \implies 20.30[/tex]
Distributive property: Remember, distributive property is about "distributing" the outside factor with each term in side the parenthesis, as follows
7. [tex]6(n+4)=6\times n + 6\times 4=6n+24[/tex]
8. [tex]15(2+r)=15 \times 2 + 15 \times r=30+15r[/tex]
9. [tex]8(s+5)=8 \times s + 8 \times 5= 8s+40[/tex]
10. [tex]3(b+8)=3b+24[/tex]
11. [tex]5(6+b)=60+5b[/tex]
12. [tex]9(3+v)=27+9v[/tex]
13. [tex]7(r-7)=7r-49[/tex]
14. [tex]12(4-v)=48-12v[/tex]
15. [tex]11(3-s)=33-3s[/tex]
The given table shows the prices. Ticket $8.50, Popcorn $5.25, Soda $4.00, Candy $3.75 and Nachos $6.
a. Each of four bought a tickets and a bag of popcorn, the money spent is
[tex]4(tickets)+4(popcorn)=4(8.50)+4(5.25)=34+21=\$55[/tex]
They spend $55 in total.
b. 12 kids buy a box of candy and a soda.
[tex]12(candy)+12(soda)=12(3.75)+12(4)=45+48=\$93[/tex]
They spent $93 in total.
c. The difference between three orders of nachos and three bags of popcorn.
[tex]3(nachos)-3(popcorn)=3(6)-3(5.25)=18-15.75=\$2.25[/tex]
So, the difference between both orders is $2.25.