Answer:
44.85C
Explanation:
Let the specific heat of glass thermometer be 0.84 J/g°C
Let the specific heat of water be 4.186 j/g °C
Let the water density be 1kg/L
136 mL of water = 0.136L of water = 0.136 kg of water = 136 g of water
Since the change of temperature on the glass thermometer is 43.6 - 22 = 21.6 C. We can then calculate the heat energy absorbed to it:
[tex]E = m_gc_g \Delta T = 39.3 * 0.84 * 21.6 = 713.06 J[/tex]
Assume no energy is lost to outside, by the law of energy conservation, this heat energy would come from water
[tex]E = m_wc_w(T - T_w) = 713.06 [/tex]
[tex] 136*4.186(T - 43.6) = 713.06[/tex]
[tex]T - 43.6 = \frac{713.06}{136*4.186} = 1.25[/tex]
[tex]T = 1.25 + 43.6 = 44.85C[/tex]
