To solve this problem we will apply the concept related to density, which is defined as a scalar magnitude referred to the amount of mass in a given volume of a substance or a solid object. Mathematically it is expressed as
[tex]\rho = \frac{m}{V}[/tex]
Here,
m = mass
V = Volume
The volume of a rectangular box will be
[tex]V = 10*5*2[/tex]
[tex]V = 100cm^3 = 1*10^{-4}m^3[/tex]
Water density is given under normal conditions such as [tex]1000kg / m ^ 3[/tex]
Therefore using the above formula and clearing for the dough we will have to
[tex]m = \rho V[/tex]
[tex]m = (1000kg/m^3)(1*10^{-4}m^3)[/tex]
[tex]m = 0.1Kg[/tex]
Therefore there are 0.1Kg of water.
